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Example of doing a multipart upload in Go (golang)
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| package main | |
| import ( | |
| "bytes" | |
| "fmt" | |
| "io" | |
| "log" | |
| "mime/multipart" | |
| "net/http" | |
| "os" | |
| "path/filepath" | |
| ) | |
| // Creates a new file upload http request with optional extra params | |
| func newfileUploadRequest(uri string, params map[string]string, paramName, path string) (*http.Request, error) { | |
| file, err := os.Open(path) | |
| if err != nil { | |
| return nil, err | |
| } | |
| defer file.Close() | |
| body := &bytes.Buffer{} | |
| writer := multipart.NewWriter(body) | |
| part, err := writer.CreateFormFile(paramName, filepath.Base(path)) | |
| if err != nil { | |
| return nil, err | |
| } | |
| _, err = io.Copy(part, file) | |
| for key, val := range params { | |
| _ = writer.WriteField(key, val) | |
| } | |
| err = writer.Close() | |
| if err != nil { | |
| return nil, err | |
| } | |
| req, err := http.NewRequest("POST", uri, body) | |
| req.Header.Set("Content-Type", writer.FormDataContentType()) | |
| return req, err | |
| } | |
| func main() { | |
| path, _ := os.Getwd() | |
| path += "/test.pdf" | |
| extraParams := map[string]string{ | |
| "title": "My Document", | |
| "author": "Matt Aimonetti", | |
| "description": "A document with all the Go programming language secrets", | |
| } | |
| request, err := newfileUploadRequest("https://google.com/upload", extraParams, "file", "/tmp/doc.pdf") | |
| if err != nil { | |
| log.Fatal(err) | |
| } | |
| client := &http.Client{} | |
| resp, err := client.Do(request) | |
| if err != nil { | |
| log.Fatal(err) | |
| } else { | |
| body := &bytes.Buffer{} | |
| _, err := body.ReadFrom(resp.Body) | |
| if err != nil { | |
| log.Fatal(err) | |
| } | |
| resp.Body.Close() | |
| fmt.Println(resp.StatusCode) | |
| fmt.Println(resp.Header) | |
| fmt.Println(body) | |
| } | |
| } |
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One of the core problems with the original example is that it requires buffering all data into into memory, which doesn't work very well if you're dealing with files.
However, it's non-obvious how to use the multi-part form in a streaming fashion - in part because the design of it is to enclose the various parts with a header and footer, which doesn't lend itself well to a typical streaming interface.
Instead, you need to create a pipe connected to the form and then and then
io.Copyeach file into that pipe after setting the headers, and then close it all out at the end.Key notes:
Do()ing the request